True when more than half the arguments are True (Orderless; symbolic simplifications)
Majority[e1, e2, …]
Majority[a]
→ aMajority[a, b]
→ a && bBooleanTable[{x, y, Majority[x, y]}, {x, y}]//Grid
→ Grid[{{True, True, True}, {True, False, False}, {False, True, False}, {False, False, False}}]